当前位置：首页 > news >正文

Python学生信息查询

news 来源：原创 2025/5/19 12:11:22

利用字典设置学生信息，将这些信息放入列表中进行存储，根据输入的姓名查询展示对应的学生信息。

Student1={'no':202001,'name':'zyt','score':87}
Student2=Student1.copy()
Student3=Student2.copy()

Student2['no']=202002
Student3['no']=202003

Student2['name']='zwh'
Student3['name']='xsy'

Student2['score']=90
Student3['score']=92

#键值对
ITEMS1=Student1.items()
ITEMS2=Student2.items()
ITEMS3=Student3.items()
#print(ITEMS1)
#print(ITEMS2)
#print(ITEMS3)

StuMessage=[]

for k1 in ITEMS1:
    #print(k1,end=",")
    StuMessage.append(list(k1))

for k2 in ITEMS2:
    #print(k2,end=",")
    StuMessage.append(list(k2))

for k3 in ITEMS3:
    #print(k3,end=",")
    StuMessage.append(list(k3))

#print("\n\n")
print("学生信息:",StuMessage)


txt=input("\n请输入学生的名字进行查询：")
txt2=str(txt)
#print("txt2:",txt2)

print("\n")

for i in StuMessage:
    #print("i是：",i)
    if txt2 in i:
        #print(StuMessage.index(i))
        #print(type(i))
        #print(StuMessage[StuMessage.index(i)-1])
        #print(i)
        #print(StuMessage[StuMessage.index(i)+1])

        Number=str(StuMessage[StuMessage.index(i)-1])
        Name=str(i)
        Score=str(StuMessage[StuMessage.index(i)+1])


        print("\t  =====================\n\t |已为您查询到相关信息：\n\t  =====================\n")
        #print("\n\n")
        Number1=Number.replace("['","")
        Number1=Number1.replace("no',","编号:")
        Number1=Number1.replace("]","")
        print("\t",Number1)

        Name1=Name.replace("['","")
        Name1=Name1.replace("name',","姓名:")
        Name1=Name1.replace("'","")
        Name1=Name1.replace("]","")
        print("\t",Name1)

        Score1=Score.replace("['","")
        Score1=Score1.replace("score',","分数:")
        Score1=Score1.replace("]","")
        print("\t",Score1)