Matrix Theory study notes[5]
文章目录
- linear space
- references
linear space
- the dimension of a linear space is maximal number of vectors among all vetor groups of linearly indepedent in the linear space.
- let n is the dimension of A which is a linear space and A is {3a,4b,6a−5∣aandbarecoprime,aandbareintegers}\{3a,4b,6a-5|a\quad and\quad b\quad are \quad coprime,a \quad and \quad b \quad are \quad integers\}{3a,4b,6a−5∣aandbarecoprime,aandbareintegers},the nnn is 2 because that the maximal numbers of vectors such as {3a,4b}\{3a,4b\}{3a,4b},{4b,6a−5}\{4b,6a-5\}{4b,6a−5} are two,dim A=2.
- the linear space A with n dimension is called as n dimension linear space AnA^nAn in the number field,if n=+∞n=+\inftyn=+∞,then A is called as unlimited dimension linear space.
- a basis of linear space meets following conditions.
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let V is a linear space in the number field K and v1,v2,v3,...,vr∈Vv_1,v_2,v_3,...,v_r \in Vv1,v2,v3,...,vr∈V,VVV satsifies two situations.
- v1,v2,v3,...,vrv_1,v_2,v_3,... ,v_rv1,v2,v3,...,vr are linear independent.
- each vector of V is the linear combination of v1,v2,v3,...,vrv_1,v_2,v_3,... ,v_rv1,v2,v3,...,vr.
the v1,v2,v3,...,vrv_1,v_2,v_3,... ,v_rv1,v2,v3,...,vrcan be called as the basis of linear space VVV,viv_ivi is basic vector.
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the basis of a linear space is not one and only.
- dimension of a linear space is the number of vectors that the basis of the linear space includes.
- the vectors which be included in fundamental resolution set of homogeneous linear equations system Ax=0Ax=0Ax=0 is a basis of solution space.
- homogeneous linear equations system,all the constant terms of it are zero,can be formed as follows.
{a11x1+a12x2+⋯+a1nxn=0a21x1+a22x2+⋯+a2nxn=0⋮am1x1+am2x2+⋯+amnxn=0\begin{cases} a_{11}x_1 + a_{12}x_2 + \cdots + a_{1n}x_n = 0 \\ a_{21}x_1 + a_{22}x_2 + \cdots + a_{2n}x_n = 0 \\ \vdots \\ a_{m1}x_1 + a_{m2}x_2 + \cdots + a_{mn}x_n = 0 \end{cases} ⎩⎨⎧a11x1+a12x2+⋯+a1nxn=0a21x1+a22x2+⋯+a2nxn=0⋮am1x1+am2x2+⋯+amnxn=0
the aija_{ij}aijis are coefficient,xjx_jxj are unkown number,the right items of all equations are zero.
- the zero solution exists necessarily, x1=x2=⋯=xn=0x_1 = x_2 = \cdots = x_n = 0x1=x2=⋯=xn=0 , to be called as trivial solution.
- the non-zero solution exists.
- if the rank rrr of a equations system’s coefficient matrix is less than the number of unkown number nnn ,r<nr<nr<n,then there are infinited number of non-zero solutions exists in the equations system,also is called as non-trivial solution.
- all solutions make up a vector space,can be called as solution space, which dimension is n−rn-rn−r.
- if the equations system has non-zero solution,then the basis of solution space can be called as fundamental system of solutions.the general solution can be expressed as a linear combination of fundamental system of solution set .
- when r=nr = nr=n,the equations system have only zero solution.
- the following example explain that how to get solution of homogeneous linear equations system.
{x1+2x2−x3=02x1−x2+x3=0\begin{cases} x_1 + 2x_2 - x_3 = 0 \\ 2x_1 - x_2 + x_3 = 0 \end{cases} {x1+2x2−x3=02x1−x2+x3=0
A=(12−12−11)A = \begin{pmatrix} 1 & 2 & -1 \\ 2 & -1 & 1 \end{pmatrix} A=(122−1−11)
(12−10−53)\begin{pmatrix} 1 & 2 & -1 \\ 0 & -5 & 3 \end{pmatrix} (102−5−13)
(101501−35)\begin{pmatrix} 1 & 0 & \frac{1}{5} \\ 0 & 1 & -\frac{3}{5} \end{pmatrix} (100151−53)
the rank r=2r = 2r=2,the number of unkown numbern=3n = 3n=3,r<nr < nr<n,the non-zero solution exists.
the free variable is x3x_3x3,let x3=5x_3 = 5x3=5
ξ=(−135)\mathbf{\xi} = \begin{pmatrix} -1 \\ 3 \\ 5 \end{pmatrix} ξ=−135
finally,the general solution has computed.
k(−135)(k∈R)k \begin{pmatrix} -1 \\ 3 \\ 5 \end{pmatrix} \quad(k \in \mathbb{R}) k−135(k∈R)
references
- deepseek
- 《矩阵论》