Codeforces Round 1027 (Div. 3)
注:这次只贴代码了, 前面文章还有好几个坑没填呢(哈哈哈)
A. Square Year
#include<bits/stdc++.h>
using namespace std;
int main(){int t; cin>>t;while(t--){string s; cin>>s;int a=stoi(s);double b=sqrt(a);if(b-int(b)>0){cout<<-1<<endl;}else{cout<<0<<" "<<b<<endl;}}return 0;
}
B. Not Quite a Palindromic String
#include<bits/stdc++.h>
using namespace std;
int main(){int t; cin>>t;while(t--){int n,k; cin>>n>>k;string s; cin>>s;vector<int> fq(2,0);for(char x: s){fq[x-'0']++;}int a=fq[0]-(n/2-k),b=fq[1]-(n/2-k);if(a>=0&&a%2==0&&b>=0&&b%2==0){cout<<"YES"<<endl;}else{cout<<"NO"<<endl;}}return 0;
}
C. Need More Arrays
#include<bits/stdc++.h>
using namespace std;
int main(){int t; cin>>t;while(t--){int n; cin>>n;vector<int> a(n);for(int i=0;i<n;i++) cin>>a[i];int cnt=1,pre=a[0];for(int i=1;i<n;i++){if(a[i]>pre+1){cnt++;pre=a[i];}}cout<<cnt<<endl;// cout<<"========"<<endl;}return 0;
}
D. Come a Little Closer
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int main() {int t;cin >> t;while (t--){int n;cin >> n;vector<vector<int>> a(n, vector<int>(2, 0));for (int i = 0; i < n; i++) {cin >> a[i][0] >> a[i][1];}if (n == 1) {cout << 1 << endl;continue;}multiset<int> xs, ys;for (auto &t : a) {xs.insert(t[0]);ys.insert(t[1]);}ll res = LONG_LONG_MAX;ll width = *xs.rbegin() - *xs.begin() + 1;ll height = *ys.rbegin() - *ys.begin() + 1;res = min(res, width * height);for (auto &t : a) {xs.erase(xs.find(t[0]));ys.erase(ys.find(t[1]));width = *xs.rbegin() - *xs.begin() + 1;height = *ys.rbegin() - *ys.begin() + 1;ll area = width * height;if (area == n - 1) {area += min(width, height);}res = min(res, area);xs.insert(t[0]);ys.insert(t[1]);}cout << res << endl;}return 0;
}
E. Kirei Attacks the Estate
#include <bits/stdc++.h>
using namespace std;
using ll=long long;
int main() {int t;cin >> t;while (t--) {int n; cin>>n;vector<ll> a(n);for(int i=0;i<n;i++) cin>>a[i];vector<vector<int>> g(n);for(int i=0;i<n-1;i++){int x,y; cin>>x>>y; x--; y--;g[x].push_back(y);g[y].push_back(x);}vector<vector<ll>> f(n,vector<ll>(2,0));auto dfs=[&](this auto&& self,int x,int fa)-> void{f[x][0]=a[x];f[x][1]=a[x];if(fa!=-1){f[x][0] = min(f[x][0], a[x]-f[fa][1]);f[x][1] = max(f[x][1], a[x]-f[fa][0]);}for(int y: g[x]){if(y!=fa) dfs(y,x);}};dfs(0,-1);for(int i=0;i<n;i++){cout<<f[i][1]<<" ";}cout<<endl;}return 0;
}
F. Small Operations
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