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实体多ID关联分页查询实例

news 来源：原创 2025/5/10 21:56:36

1.Controller 层接口

@RestController
@RequestMapping("/api/user")
public class UserController {

    @Autowired
    private UserService userService;

    @GetMapping("/list")
    public ApiResponse<Page<UserVO>> listUserPage(
        @RequestParam(defaultValue = "1") Integer pageNum,
        @RequestParam(defaultValue = "10") Integer pageSize,
        UserQueryDTO queryDTO
    ) {
        Page<UserVO> page = new Page<>(pageNum, pageSize);
        return ApiResponse.success(userService.listUserPage(page, queryDTO));
    }
}

2.Service 实现

@Override
public Page<UserVO> listUserPage(Page<UserVO> page, UserQueryDTO queryDTO) {
    return baseMapper.listUserPage(page, queryDTO);
}

3.Mapper 接口

public interface UserMapper extends BaseMapper<User> {
    Page<UserVO> listUserPage(Page<UserVO> page, @Param("query") UserQueryDTO queryDTO);
}

4.XML 映射文件

<!-- UserMapper.xml -->
<select id="listUserPage" resultType="com.example.vo.UserVO">
    SELECT 
        u.id, 
        u.username,
        ut.name AS userTypeName,
        d.name AS deptName,
        p.name AS positionName
    FROM user u
    LEFT JOIN user_type ut ON u.user_type_id = ut.id
    LEFT JOIN dept d ON u.dept_id = d.id
    LEFT JOIN position p ON u.position_id = p.id
    <where>
        <if test="query.username != null and query.username != ''">
            u.username LIKE CONCAT('%', #{query.username}, '%')
        </if>
    </where>
</select>