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C语言实现android/linux按键模拟

news 来源：原创 2025/5/20 5:46:15

C语言实现 input事件模拟

#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <linux/input.h>int main() {int fd = open("/dev/input/event0", O_RDWR);if (fd < 0) {perror("Failed to open device");return -1;}// 定义 8 个输入事件（按顺序模拟按键按下和释放）struct input_event events[] = {// KEY_314 按下{.type = EV_KEY, .code = 314, .value = 1},{.type = EV_SYN, .code = SYN_REPORT, .value = 0},// KEY_212 按下{.type = EV_KEY, .code = 212, .value = 1},{.type = EV_SYN, .code = SYN_REPORT, .value = 0},// KEY_212 释放{.type = EV_KEY, .code = 212, .value = 0},{.type = EV_SYN, .code = SYN_REPORT, .value = 0},// KEY_314 释放{.type = EV_KEY, .code = 314, .value = 0},{.type = EV_SYN, .code = SYN_REPORT, .value = 0}};// 批量发送事件for (int i = 0; i < sizeof(events)/sizeof(events[0]); i++) {if (write(fd, &events[i], sizeof(struct input_event)) < 0) {perror("Failed to send event");close(fd);return -1;}}close(fd);return 0;
}

静态交叉编译

aarch64-linux-gnu-gcc-10   123.c -o startup_camera_common --static

可以模拟简单按键事件

为什么不用 shell命令

比如
adb shell “sendevent /dev/input/event0 0001 314 00000001”
adb shell “sendevent /dev/input/event0 0000 0000 00000000”
adb shell “sendevent /dev/input/event0 0001 212 00000001”
adb shell “sendevent /dev/input/event0 0000 0000 00000000”

adb shell “sendevent /dev/input/event0 0001 212 00000000”
adb shell “sendevent /dev/input/event0 0000 0000 00000000”
adb shell “sendevent /dev/input/event0 0001 314 00000000”
adb shell “sendevent /dev/input/event0 0000 0000 00000000”

sendevent 是 busybox命令, 每次执行八条命令耗时过长, 在抓 perfetto的时候会看到耗时特别久, 对于分析按键触发的性能事件有很大的干扰!