【力扣 简单 C】206. 反转链表

目录

题目

解法一：迭代

解法二：递归

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题目

解法一：迭代

struct ListNode* reverse(struct ListNode* head)
{struct ListNode* retHead = NULL;while (head){struct ListNode* nextNode = head->next;head->next = retHead;retHead = head;head = nextNode;}return retHead;
}struct ListNode* reverseList(struct ListNode* head)
{return reverse(head);
}

解法二：递归

struct ListNode* reverse(struct ListNode* head)
{if (!head || !head->next)return head;struct ListNode* retHead = reverse(head->next);head->next->next = head;head->next = NULL;return retHead;
}struct ListNode* reverseList(struct ListNode* head)
{return reverse(head);
}