seo网站制作优化做食品网站需要什么

背景

在 node 端执行打开一个新的 chrome 浏览器 并且跳转到指定 url

注意不是在原有浏览器打开新页签

代码

talking is cheap, show me the code

  @Get('/url')async getUser(@Query('url') url: string): Promise<any> {try {if (!url) {return {success: false,error: 'URL参数不能为空',};}let targetUrl = url;if (!url.startsWith('http://') && !url.startsWith('https://')) {targetUrl = `https://${url}`;}const isWin = process.platform === 'win32';const isMac = process.platform === 'darwin';const isLinux = process.platform === 'linux';let command: string;if (isMac) {command = `osascript -e 'tell application "Google Chrome" to make new window' -e 'tell application "Google Chrome" to set URL of active tab of front window to "${targetUrl}"'`;} else if (isWin) {command = `start chrome --new-window "${targetUrl}"`;} else if (isLinux) {command = `google-chrome --new-window "${targetUrl}"`;} else {return {success: false,error: '不支持的操作系统',};}exec(command, (error, stdout, stderr) => {if (error) {console.error('打开Chrome失败:', error);}if (stderr) {console.error('Chrome错误输出:', stderr);}if (stdout) {console.log('Chrome输出:', stdout);}});return {success: true,url: targetUrl,message: '正在打开Chrome浏览器...',};} catch (error) {return {success: false,error: error.message,};}}