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Rust 练习册 ：Rail Fence Cipher与栅栏密码

news 2025/11/9 7:20:17

栅栏密码（Rail Fence Cipher）是一种经典的置换密码，通过将明文按对角线方式写在多个"轨道"上，然后按行读取来实现加密。在 Exercism 的 “rail-fence-cipher” 练习中，我们需要实现栅栏密码的加密和解密功能。这不仅能帮助我们掌握字符串处理和算法设计技巧，还能深入学习Rust中的结构体设计、索引计算和字符操作。

什么是栅栏密码？

栅栏密码是一种置换密码，通过将明文按Z字形方式写在多个轨道（rails）上，然后按行读取来实现加密。解密过程则是相反的操作。

例如，使用3个轨道加密 “WEAREDISCOVEREDFLEEATONCE”：

W . . . E . . . C . . . R . . . L . . . T . . . E
. E . R . D . S . O . E . E . F . E . A . O . C .
. . A . . . I . . . V . . . D . . . E . . . N . .

按行读取得到密文：“WECRLTEERDSOEEFEAOCAIVDEN”

让我们先看看练习提供的结构体和函数：

pub struct RailFence;impl RailFence {pub fn new(rails: u32) -> RailFence {unimplemented!("Construct a new fence with {} rails", rails)}pub fn encode(&self, text: &str) -> String {unimplemented!("Encode this text: {}", text)}pub fn decode(&self, cipher: &str) -> String {unimplemented!("Decode this ciphertext: {}", cipher)}
}

我们需要实现 RailFence 结构体，使其能够进行栅栏密码的加密和解密操作。

设计分析

1. 核心要求

  1. 结构体设计：设计 RailFence 结构体存储轨道数
  2. 加密实现：实现按Z字形方式排列字符的加密算法
  3. 解密实现：实现根据密文和轨道数还原明文的解密算法
  4. 字符处理：正确处理各种字符，包括宽字符

2. 技术要点

  1. Z字形模式：理解和实现字符在轨道间的Z字形分布
  2. 索引计算：计算字符在轨道中的位置
  3. 字符串操作：高效处理和重组字符串
  4. 算法设计：设计加密和解密算法

完整实现

1. 基础实现

pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> RailFence {RailFence { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<Vec<char>> = vec![Vec::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails.into_iter().flatten().collect()}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;// 计算每个轨道的字符数量for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 将密文分割到各个轨道let chars: Vec<char> = cipher.chars().collect();let mut rails: Vec<Vec<char>> = vec![Vec::new(); n];let mut start = 0;for i in 0..n {let end = start + rail_lengths[i];rails[i] = chars[start..end].to_vec();start = end;}// 重新构建明文let mut result = String::new();let mut rail_indices = vec![0; n];rail = 0;step = 1;for _ in 0..len {result.push(rails[rail][rail_indices[rail]]);rail_indices[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}result}
}

2. 优化实现

pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> RailFence {RailFence { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<String> = vec![String::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails.concat()}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();// 计算每个轨道的字符数量let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 将密文分割到各个轨道let chars: Vec<char> = cipher.chars().collect();let mut rails: Vec<&[char]> = Vec::with_capacity(n);let mut start = 0;for &length in &rail_lengths {let end = start + length;rails.push(&chars[start..end]);start = end;}// 重新构建明文let mut result = String::with_capacity(len);let mut rail_indices = vec![0; n];rail = 0;let mut step = 1;for _ in 0..len {result.push(rails[rail][rail_indices[rail]]);rail_indices[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}result}
}

3. 使用索引计算的实现

pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> RailFence {RailFence { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let chars: Vec<char> = text.chars().collect();let len = chars.len();// 计算每个字符应该放在哪个轨道let mut rail_indices: Vec<usize> = Vec::with_capacity(len);let mut rail = 0;let mut step = 1;for _ in 0..len {rail_indices.push(rail);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 按轨道收集字符let mut result = String::with_capacity(len);for target_rail in 0..n {for (i, &char_rail) in rail_indices.iter().enumerate() {if char_rail == target_rail {result.push(chars[i]);}}}result}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();// 计算每个字符原来的位置let mut rail_indices: Vec<usize> = Vec::with_capacity(len);let mut rail = 0;let mut step = 1;for _ in 0..len {rail_indices.push(rail);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 构建位置映射let mut positions: Vec<(usize, usize)> = rail_indices.iter().enumerate().map(|(original, &rail)| (rail, original)).collect();// 按轨道和原始位置排序positions.sort_by(|a, b| {if a.0 == b.0 {a.1.cmp(&b.1)} else {a.0.cmp(&b.0)}});// 解密let cipher_chars: Vec<char> = cipher.chars().collect();let mut result_chars = vec![' '; len];for (i, &(_, original_pos)) in positions.iter().enumerate() {result_chars[original_pos] = cipher_chars[i];}result_chars.iter().collect()}
}

测试用例分析

通过查看测试用例，我们可以更好地理解需求：

#[test]
/// encode with two rails
fn test_encode_with_two_rails() {process_encode_case("XOXOXOXOXOXOXOXOXO", 2, "XXXXXXXXXOOOOOOOOO");
}

使用2个轨道加密，将字符按X和O分组。

#[test]
/// encode with three rails
fn test_encode_with_three_rails() {process_encode_case("WEAREDISCOVEREDFLEEATONCE", 3, "WECRLTEERDSOEEFEAOCAIVDEN");
}

使用3个轨道加密经典的示例文本。

#[test]
/// encode with ending in the middle
fn test_encode_with_ending_in_the_middle() {process_encode_case("EXERCISES", 4, "ESXIEECSR");
}

使用4个轨道加密，结束位置在中间轨道。

#[test]
/// decode with three rails
fn test_decode_with_three_rails() {process_decode_case("TEITELHDVLSNHDTISEIIEA", 3, "THEDEVILISINTHEDETAILS");
}

使用3个轨道解密。

#[test]
/// decode with five rails
fn test_decode_with_five_rails() {process_decode_case("EIEXMSMESAORIWSCE", 5, "EXERCISMISAWESOME");
}

使用5个轨道解密。

#[test]
/// decode with six rails
fn test_decode_with_six_rails() {process_decode_case("133714114238148966225439541018335470986172518171757571896261",6,"112358132134558914423337761098715972584418167651094617711286",);
}

使用6个轨道解密数字字符串。

#[test]
/// encode wide characters
///
/// normally unicode is not part of exercism exercises, but in an exercise
/// specifically oriented around shuffling characters, it seems worth ensuring
/// that wide characters are handled properly
///
/// this text is possibly one of the most famous haiku of all time, by
/// Matsuo Bashō (松尾芭蕉)
fn test_encode_wide_characters() {process_encode_case("古池蛙飛び込む水の音", 3, "古びの池飛込水音蛙む");
}

处理宽字符（日文）的加密。

性能优化版本

考虑性能的优化实现：

pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> RailFence {RailFence { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let len = text.chars().count();// 预分配结果字符串let mut result = String::with_capacity(len);// 对于每个轨道，直接计算应该放置哪些字符let chars: Vec<char> = text.chars().collect();for rail in 0..n {let mut pos = rail;let mut down = rail != n - 1;let mut up = rail != 0;while pos < len {result.push(chars[pos]);if down && up {// 中间轨道，交替方向pos += 2 * (n - 1 - rail);std::mem::swap(&mut down, &mut up);} else if down {// 底部轨道，只向上pos += 2 * (n - 1 - rail);} else {// 顶部轨道，只向下pos += 2 * rail;}}}result}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();let cipher_chars: Vec<char> = cipher.chars().collect();// 预分配结果let mut result = vec![' '; len];// 计算每个轨道的长度let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 构建每个轨道的字符索引let mut rail_chars: Vec<Vec<char>> = vec![Vec::new(); n];let mut start = 0;for i in 0..n {let end = start + rail_lengths[i];rail_chars[i] = cipher_chars[start..end].to_vec();start = end;}// 重新构建明文let mut rail_indices = vec![0; n];rail = 0;let mut step = 1;let mut pos = 0;while pos < len {result[pos] = rail_chars[rail][rail_indices[rail]];rail_indices[rail] += 1;pos += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}result.iter().collect()}
}// 使用字节操作的版本（仅适用于ASCII字符）
pub struct RailFenceBytes {rails: u32,
}impl RailFenceBytes {pub fn new(rails: u32) -> RailFenceBytes {RailFenceBytes { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 || !text.is_ascii() {return text.to_string();}let n = self.rails as usize;let bytes = text.as_bytes();let len = bytes.len();let mut result = Vec::with_capacity(len);let mut rails: Vec<Vec<u8>> = vec![Vec::new(); n];let mut rail = 0;let mut step = 1;for &byte in bytes {rails[rail].push(byte);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}for rail_content in rails {result.extend(rail_content);}String::from_utf8(result).unwrap_or_else(|_| text.to_string())}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 || !cipher.is_ascii() {return cipher.to_string();}let n = self.rails as usize;let len = cipher.as_bytes().len();let bytes = cipher.as_bytes();// 计算每个轨道的字符数量let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 将密文分割到各个轨道let mut rails: Vec<&[u8]> = Vec::with_capacity(n);let mut start = 0;for &length in &rail_lengths {let end = start + length;rails.push(&bytes[start..end]);start = end;}// 重新构建明文let mut result = Vec::with_capacity(len);let mut rail_indices = vec![0; n];rail = 0;step = 1;for _ in 0..len {result.push(rails[rail][rail_indices[rail]]);rail_indices[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}String::from_utf8(result).unwrap_or_else(|_| cipher.to_string())}
}

错误处理和边界情况

考虑更多边界情况的实现：

#[derive(Debug, PartialEq)]
pub enum RailFenceError {InvalidRails,EmptyText,
}impl std::fmt::Display for RailFenceError {fn fmt(&self, f: &mut std::fmt::Formatter) -> std::fmt::Result {match self {RailFenceError::InvalidRails => write!(f, "轨道数必须大于0"),RailFenceError::EmptyText => write!(f, "文本不能为空"),}}
}impl std::error::Error for RailFenceError {}pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> Result<RailFence, RailFenceError> {if rails == 0 {Err(RailFenceError::InvalidRails)} else {Ok(RailFence { rails })}}pub fn encode(&self, text: &str) -> String {if text.is_empty() {return String::new();}if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<String> = vec![String::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails.concat()}pub fn decode(&self, cipher: &str) -> String {if cipher.is_empty() {return String::new();}if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();// 计算每个轨道的字符数量let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 将密文分割到各个轨道let chars: Vec<char> = cipher.chars().collect();let mut rails: Vec<&[char]> = Vec::with_capacity(n);let mut start = 0;for &length in &rail_lengths {let end = start + length;rails.push(&chars[start..end]);start = end;}// 重新构建明文let mut result = String::with_capacity(len);let mut rail_indices = vec![0; n];rail = 0;let mut step = 1;for _ in 0..len {result.push(rails[rail][rail_indices[rail]]);rail_indices[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}result}// 返回Result的版本pub fn encode_safe(&self, text: &str) -> Result<String, RailFenceError> {if text.is_empty() {Err(RailFenceError::EmptyText)} else {Ok(self.encode(text))}}pub fn decode_safe(&self, cipher: &str) -> Result<String, RailFenceError> {if cipher.is_empty() {Err(RailFenceError::EmptyText)} else {Ok(self.decode(cipher))}}
}// 支持可变轨道数的版本
pub struct DynamicRailFence {rails: u32,
}impl DynamicRailFence {pub fn new(rails: u32) -> DynamicRailFence {DynamicRailFence { rails }}pub fn set_rails(&mut self, rails: u32) {self.rails = rails;}pub fn encode(&self, text: &str) -> String {let fence = RailFence::new(self.rails).unwrap();fence.encode(text)}pub fn decode(&self, cipher: &str) -> String {let fence = RailFence::new(self.rails).unwrap();fence.decode(cipher)}
}

扩展功能

基于基础实现，我们可以添加更多功能：

pub struct RailFence {rails: u32,
}impl RailFence {pub fn new(rails: u32) -> RailFence {RailFence { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<String> = vec![String::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails.concat()}pub fn decode(&self, cipher: &str) -> String {if self.rails <= 1 {return cipher.to_string();}let n = self.rails as usize;let len = cipher.chars().count();let mut rail_lengths = vec![0; n];let mut rail = 0;let mut step = 1;for _ in 0..len {rail_lengths[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}let chars: Vec<char> = cipher.chars().collect();let mut rails: Vec<&[char]> = Vec::with_capacity(n);let mut start = 0;for &length in &rail_lengths {let end = start + length;rails.push(&chars[start..end]);start = end;}let mut result = String::with_capacity(len);let mut rail_indices = vec![0; n];rail = 0;let mut step = 1;for _ in 0..len {result.push(rails[rail][rail_indices[rail]]);rail_indices[rail] += 1;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}result}// 分析栅栏密码结构pub fn analyze(&self, text: &str) -> RailFenceAnalysis {let encoded = self.encode(text);let pattern = self.get_rail_pattern(text.len());RailFenceAnalysis {original_text: text.to_string(),encoded_text: encoded,rail_count: self.rails,text_length: text.len(),rail_pattern: pattern,}}// 获取轨道模式fn get_rail_pattern(&self, length: usize) -> Vec<usize> {if self.rails <= 1 {return vec![0; length];}let n = self.rails as usize;let mut pattern = Vec::with_capacity(length);let mut rail = 0;let mut step = 1;for _ in 0..length {pattern.push(rail);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}pattern}// 获取每个轨道的字符pub fn get_rail_contents(&self, text: &str) -> Vec<String> {if self.rails <= 1 {return vec![text.to_string()];}let n = self.rails as usize;let mut rails: Vec<String> = vec![String::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails}
}pub struct RailFenceAnalysis {pub original_text: String,pub encoded_text: String,pub rail_count: u32,pub text_length: usize,pub rail_pattern: Vec<usize>,
}// 栅栏密码工具箱
pub struct RailFenceToolkit;impl RailFenceToolkit {pub fn new() -> Self {RailFenceToolkit}// 尝试不同的轨道数进行解密pub fn brute_force_decode(&self, cipher: &str, max_rails: u32) -> Vec<(u32, String)> {let mut results = Vec::new();for rails in 2..=max_rails {let fence = RailFence::new(rails);let decoded = fence.decode(cipher);results.push((rails, decoded));}results}// 分析密文可能的轨道数pub fn analyze_rail_count(&self, cipher: &str) -> Vec<u32> {let len = cipher.chars().count();let mut possible_rails = Vec::new();// 轨道数必须在合理范围内for rails in 2..=((len / 2) as u32 + 1).min(10) {// 简单启发式检查if len % (rails as usize) == 0 || len % (rails as usize - 1) == 0 {possible_rails.push(rails);}}possible_rails}// 格式化显示栅栏密码结构pub fn display_rail_fence(&self, text: &str, rails: u32) -> String {if rails <= 1 {return text.to_string();}let n = rails as usize;let chars: Vec<char> = text.chars().collect();let len = chars.len();// 创建显示网格let mut grid: Vec<Vec<char>> = vec![vec!['.'; len]; n];let mut rail = 0;let mut step = 1;for (i, &c) in chars.iter().enumerate() {grid[rail][i] = c;if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}// 格式化输出grid.iter().map(|row| row.iter().collect::<String>()).collect::<Vec<String>>().join("\n")}
}// 便利函数
pub fn encode_rail_fence(text: &str, rails: u32) -> String {let fence = RailFence::new(rails);fence.encode(text)
}pub fn decode_rail_fence(cipher: &str, rails: u32) -> String {let fence = RailFence::new(rails);fence.decode(cipher)
}pub fn format_rail_fence_analysis(text: &str, rails: u32) -> String {let fence = RailFence::new(rails);let analysis = fence.analyze(text);format!("原文: {}\n密文: {}\n轨道数: {}\n长度: {}\n轨道模式: {:?}",analysis.original_text,analysis.encoded_text,analysis.rail_count,analysis.text_length,analysis.rail_pattern)
}

实际应用场景

栅栏密码在实际开发中有以下应用：

  1. 密码学教学：经典密码算法教学和演示
  2. 游戏开发：解密游戏和益智游戏
  3. 教育软件：密码学和信息安全教学工具
  4. 文本处理：特殊文本格式化和处理
  5. 历史研究：古典密码研究和分析
  6. 编程练习：算法设计和字符串处理练习
  7. 安全通信：简单的文本混淆和隐私保护
  8. 艺术创作：创意文本排版和视觉设计

算法复杂度分析

  1. 时间复杂度：

    • 加密：O(n)，其中n是文本长度
    • 解密：O(n)，其中n是密文长度

  2. 空间复杂度：O(n)

    • 需要存储轨道中的字符和结果字符串

与其他实现方式的比较

// 使用递归的实现
pub struct RailFenceRecursive {rails: u32,
}impl RailFenceRecursive {pub fn new(rails: u32) -> RailFenceRecursive {RailFenceRecursive { rails }}pub fn encode(&self, text: &str) -> String {fn encode_recursive(chars: &[char],rails: usize,rail: usize,step: i32,index: usize,rail_chars: &mut [String],) {if index >= chars.len() {return;}rail_chars[rail].push(chars[index]);let (new_rail, new_step) = if rail == 0 {(1, 1)} else if rail == rails - 1 {(rails - 2, -1)} else {((rail as i32 + step) as usize, step)};encode_recursive(chars, rails, new_rail, new_step, index + 1, rail_chars);}if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let chars: Vec<char> = text.chars().collect();let mut rails: Vec<String> = vec![String::new(); n];encode_recursive(&chars, n, 0, 1, 0, &mut rails);rails.concat()}
}// 使用第三方库的实现
// [dependencies]
// itertools = "0.10"use itertools::Itertools;pub struct RailFenceItertools {rails: u32,
}impl RailFenceItertools {pub fn new(rails: u32) -> RailFenceItertools {RailFenceItertools { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<Vec<char>> = vec![Vec::new(); n];let mut rail = 0;let mut step = 1;for c in text.chars() {rails[rail].push(c);if rail == 0 {step = 1;} else if rail == n - 1 {step = -1;}rail = (rail as i32 + step) as usize;}rails.into_iter().flatten().collect()}
}// 使用状态机的实现
#[derive(Debug, Clone, Copy)]
enum RailDirection {Down,Up,
}pub struct RailFenceStateMachine {rails: u32,
}impl RailFenceStateMachine {pub fn new(rails: u32) -> RailFenceStateMachine {RailFenceStateMachine { rails }}pub fn encode(&self, text: &str) -> String {if self.rails <= 1 {return text.to_string();}let n = self.rails as usize;let mut rails: Vec<String> = vec![String::new(); n];let mut current_rail = 0;let mut direction = RailDirection::Down;for c in text.chars() {rails[current_rail].push(c);match direction {RailDirection::Down => {if current_rail == n - 1 {direction = RailDirection::Up;current_rail = n - 2;} else {current_rail += 1;}}RailDirection::Up => {if current_rail == 0 {direction = RailDirection::Down;current_rail = 1;} else {current_rail -= 1;}}}}rails.concat()}
}

总结

通过 rail-fence-cipher 练习，我们学到了：

  1. 字符串处理：掌握了复杂的字符串处理和字符重排技巧
  2. 算法设计：学会了实现Z字形模式的算法设计
  3. 结构体设计：理解了如何设计合适的数据结构存储状态
  4. 索引计算：深入理解了复杂索引模式的计算方法
  5. 性能优化：学会了预分配内存和使用高效算法等优化技巧
  6. 边界处理：理解了如何处理各种边界情况

这些技能在实际开发中非常有用，特别是在密码学、文本处理、游戏开发等场景中。栅栏密码虽然是一个经典的密码学问题，但它涉及到了字符串处理、算法设计、索引计算、性能优化等许多核心概念，是学习Rust实用编程的良好起点。

通过这个练习，我们也看到了Rust在字符串处理和算法实现方面的强大能力，以及如何用安全且高效的方式实现经典的密码学算法。这种结合了安全性和性能的语言特性正是Rust的魅力所在。

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