C语言机试编程题

编写版本：vc++2022

1.求最大/小值

#include<stdio.h>
int main(){
	int a[50],n;
	int max, min;
	printf("请输入您要输入几个数");
	scanf_s("%d", &n);
	printf("请输入您要比较的%d个数\n",n);
	for (int i = 0; i<n; i++) {
		scanf_s("%d", &a[i]);
	}
	max = min = a[0];
	for (int i = 0; i < n; i++) {
		if (a[i] > max) max = a[i];
		if (a[i] < min) min = a[i];
	}
	printf("max=%d,min=%d", max, min);
	return 0;
}

2.求一个三位数abc，使a的阶乘+b的阶乘+c的阶乘=abc

#include<stdio.h>
//factorial 阶乘
int jiecheng(int n) {
	int m=1;
	while (n != 0) {
		m *= n;
		n--;
	}
	return m;
}
int main() {
	int a, b, c;
	for (int abc = 100; abc <= 999; abc++) {
		a = abc / 100;
		b = abc / 10 % 10;
		c = abc % 10;
		if (abc == jiecheng(a) + jiecheng(b) + jiecheng(c))
			printf("%d\n", abc);
	}
	return 0;
}

3.求2/1，3/2，5/3，8/5，13/8，21/13，的前20项和

#include<stdio.h>
int main() {
	float sum = 2;
	int i = 1, j = 2;
	float k;
	for (int num = 1; num < 20; num++) {
		k = i + j;
		i = j;
		sum += k / i;
		j = k;
	}
	printf("%0.2f", sum);
	return 0;
}

4.求阶乘

#include<stdio.h>
int main() {
	int N;
	int jiecheng=1;
	scanf_s("%d", &N);
	while (N != 0) {
		jiecheng *= N;
		N--;
	}
	printf("%d\n", jiecheng);
	return 0;
}

5.求10-1000之间所有数字之和为5的整数的个数

#include<stdio.h>
int main() {
	int count = 0;
	for (int i = 10; i <= 99; i++) {//两位数
		if (i/10+i%10== 5)
			count++;
	}
	for (int i = 100; i <= 999; i++) {//三位数
		if ((i/100)+(i/10%10)+(i%10)== 5)
			count++;
	}
	printf("%d\n", count);
	return 0;
}

6.输入字符串打印除小写，元音，字母之外的。用数组

#include<stdio.h>
int main() {
	char a[50];
	scanf_s("%s", a, 50);
	for (int i = 0; a[i] != '\0'; i++)
		if (a[i] != 'a' && a[i] != 'e' && a[i] != 'i' && a[i] != 'o' && a[i] != 'u')
			printf("%c", a[i]);
	return 0;
}

scanf_s输入字符串时，需要添加长度防止溢出

7.计算输入的10个整数中的，偶数的和，偶数平均值（小数表示）

#include<stdio.h>
int main() {
	int a[10];
	int sum=0;
	double avg;
	for (int i = 0; i < 10; i++) {
		scanf_s("%d", &a[i]);
		if (a[i] % 2 == 0) sum += a[i];
	}
	avg = sum / 10.0;
	printf("偶数的和%d,偶数的平均值%0.2f", sum, avg);
	return 0;
}

8.循环语句求a+aa+aaa+aaaa……n个a，n和a由键盘输入

#include<stdio.h>
#include<math.h>
int main() {
	int a, n,m;
	int sum = 0;
	scanf_s("%d %d", &a, &n);
	m = a;
	for (int i = 1; i <= n; i++) {
		sum += m;
		m += a * pow(10, i);
	}
	printf("%d", sum);
	return 0;
}

9.1！+2！+3！+4！……

#include<stdio.h>
int main() {
	int sum = 0, n,m=1;
	scanf_s("%d", &n);
	for (int i = 1; i <= n; i++) {
		m *= i;
		sum += m;
	}
	printf("%d", sum);
	return 0;
}