C++ set数据插入、set数据查找、set数据删除、set数据统计、set排序规则、代码练习1、2
set数据插入,代码见下
#include<iostream>
#include<set>
#include<vector>using namespace std;void printSet(const set<int>& s) {for (set<int>::const_iterator it = s.begin(); it != s.end(); it++) {cout << *it << " ";}cout << endl;
}int main() {// 树形结构插入的时间复杂度为 O(logn)// 直接插入值set<int> s;s.insert(4);s.insert(3);s.insert(8);// 迭代器插入vector<int> a = { 4, 5, 9 };s.insert(a.begin(), a.end());printSet(s); // 重复的值不会插入return 0;
}
结果见下,辅助理解:
3 4 5 8 9
set数据查找,代码见下:
#include<iostream>
#include<set>
#include<vector>using namespace std;void printSet(const set<int>& s) {for (set<int>::const_iterator it = s.begin(); it != s.end(); it++) {cout << *it << " ";}cout << endl;
}int main() {set<int> s = { 8, 5, 9, 2, 1, 3 };set<int>::iterator it = s.find(3);if (it != s.end()) {cout << "find" << (*it) << endl;}it = s.find(10);if (it == s.end()) {cout << "can't find" << endl;}return 0;
}
set数据删除,代码见下:
#include<iostream>
#include<set>
#include<vector>using namespace std;void printSet(const set<int>& s) {for (set<int>::const_iterator it = s.begin(); it != s.end(); it++) {cout << *it << " ";}cout << endl;
}int main() {set<int> s = { 8, 5, 9, 2, 4, 1, 3 };s.erase(2);printSet(s);set<int>::iterator rm = s.find(4);if (rm != s.end()) {s.erase(rm);}printSet(s);s = { 1, 2, 3, 4, 5 };set<int>::iterator rml = s.find(2); // 删除元素后,迭代器就失效了set<int>::iterator rmr = s.find(4);s.erase(rml, rmr);// 左闭右开区间 [ ) 不删除4printSet(s);return 0;
}
结果见下,辅助理解
1 3 4 5 8 9
1 3 5 8 9
1 4 5
set数据统计,代码见下:
#include<iostream>
#include<set>
#include<vector>using namespace std;void printSet(const set<int>& s) {for (set<int>::const_iterator it = s.begin(); it != s.end(); it++) {cout << *it << " ";}cout << endl;
}void printmultiSet(const multiset<int>& s) {for (multiset<int>::const_iterator it = s.begin(); it != s.end(); it++) {cout << *it << " ";}cout << endl;
}int main() {set<int> s = { 4, 5, 7, 9, 3 };for (int i = 0; i < 8; ++i) {cout << "元素:" << i << "的出现次数为:" << s.count(i) << endl;}multiset<int> ms = { 1, 1, 1, 2, 2, 3, 7, 7, 7 };for (int i = 0; i < 8; ++i) {cout << "元素:" << i << "的出现次数为:" << ms.count(i) << endl;}printmultiSet(ms);return 0;
}
结果见下,有助理解:
元素:0的出现次数为:0
元素:1的出现次数为:0
元素:2的出现次数为:0
元素:3的出现次数为:1
元素:4的出现次数为:1
元素:5的出现次数为:1
元素:6的出现次数为:0
元素:7的出现次数为:1
元素:0的出现次数为:0
元素:1的出现次数为:3
元素:2的出现次数为:2
元素:3的出现次数为:1
元素:4的出现次数为:0
元素:5的出现次数为:0
元素:6的出现次数为:0
元素:7的出现次数为:3
1 1 1 2 2 3 7 7 7
set排序规则,以下是属于结构体的情况,代码见下:
#include<iostream>
#include<set>
#include<vector>using namespace std;class CGAGA {
public:CGAGA() {_name = "";_priority = -1;}CGAGA(string name, int pri) : _name(name), _priority(pri) {}bool operator<(const CGAGA& other) const {return _priority < other._priority;}void print() const {cout << "(" << _priority << ")" << _name << endl;}
private:string _name;int _priority;
};int main() {set<CGAGA> s;s.insert(CGAGA("C++算法零基础", 5));s.insert(CGAGA("C++面向对象", 4));s.insert(CGAGA("C++stl", 3));s.insert(CGAGA("C++项目实战", 2));s.insert(CGAGA("C++算法零基础2", 1));for (set<CGAGA>::iterator it = s.begin(); it != s.end(); it++) {(*it).print();}return 0;
}
结果见下,助于理解
(1)C++算法零基础2
(2)C++项目实战
(3)C++stl
(4)C++面向对象
(5)C++算法零基础