【LaTeX】Misplaced alignment tab character . ^^I

目录

公式中出现Misplaced alignment tab character &. ^^I&

解决1：采用&=&

解决2：

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公式中出现Misplaced alignment tab character &. ^^I&

	\begin{equation}J_r & =\dfrac{i\hbar}{2m}\left[\psi_2 \dfrac{\partial \psi^*_2}{\partial r} -\psi^* \dfrac{\partial \psi_2}{\partial r}\right] \notag \\& =\dfrac{i \hbar}{2m}|f(\theta,\varphi)|^2\left[- \frac{i k}{r^2}-\dfrac{i k}{r^2}\right] \\& =\dfrac{v}{r^2}|f(\theta,\varphi)|^2\notag\end{equation}	

Latex编辑出现Misplaced alignment tab character &. 解决办法 - 代码先锋网

[Latex] 在公式环境下报错：Misplaced alignment tab character &. - 代码先锋网

\begin{eqnarray}J_r & =\dfrac{i\hbar}{2m}\left[\psi_2 \dfrac{\partial \psi^*_2}{\partial r} -\psi^* \dfrac{\partial \psi_2}{\partial r}\right] \notag \\& =\dfrac{i \hbar}{2m}|f(\theta,\varphi)|^2\left[- \frac{i k}{r^2}-\dfrac{i k}{r^2}\right] \\& =\dfrac{v}{r^2}|f(\theta,\varphi)|^2\notag\end{eqnarray}	

还是没有对齐

解决1：采用&=&

\begin{eqnarray}J_r & =&\dfrac{i\hbar}{2m}\left[\psi_2 \dfrac{\partial \psi^*_2}{\partial r} -\psi^* \dfrac{\partial \psi_2}{\partial r}\right] \notag \\& =&\dfrac{i \hbar}{2m}|f(\theta,\varphi)|^2\left[- \frac{i k}{r^2}-\dfrac{i k}{r^2}\right] \\& =&\dfrac{v}{r^2}|f(\theta,\varphi)|^2\notag\end{eqnarray}

解决latex报错：Misplaced alignment tab character &. System Safety} - 知乎

解决2：

为了使等号对齐，建议使用 align 环境代替 eqnarray，并调整 & 的位置。以下是修正后的代码：

\begin{align}J_r & = \dfrac{i\hbar}{2m}\left[\psi_2 \dfrac{\partial \psi^*_2}{\partial r} -\psi^* \dfrac{\partial \psi_2}{\partial r}\right] \notag \\& = \dfrac{i \hbar}{2m}|f(\theta,\varphi)|^2\left[- \frac{i k}{r^2}-\dfrac{i k}{r^2}\right] \tag{1} \\& = \dfrac{v}{r^2}|f(\theta,\varphi)|^2 \notag\end{align}

想要接着之前的编号怎么办？

\begin{align}J_r & = \dfrac{i\hbar}{2m}\left[\psi_2 \dfrac{\partial \psi^*_2}{\partial r} -\psi^* \dfrac{\partial \psi_2}{\partial r}\right] \notag \\& = \dfrac{i \hbar}{2m}|f(\theta,\varphi)|^2\left[- \frac{i k}{r^2}-\dfrac{i k}{r^2}\right] \label{eq:current} \\  % 自动延续之前的编号（例如原编号为 2，此行会标为 3）& = \dfrac{v}{r^2}|f(\theta,\varphi)|^2 \notag\end{align}