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 c++ 20中引入了latch和barrier，提供了一种简单的同步机制，来协调多个线程

线程屏障提供了一个计数器，每个参与任务的线程完成自己的任务后，计数器减1.而需要同步的线程，屏障计数器可以阻塞，等待计数器为0时，继续执行后面的代码。

latch为一次性计数，当计数为0时就不能重复使用了。而barrirer为多个阶段的计数。

下面模拟一个比赛：发令枪响起，选手开跑，全部选手到达终点后统计成绩。

#include<array>
#include<vector>
#include<thread>
#include<iostream>
#include<mutex>
#include<algorithm>
#include<sstream>
#include<iomanip>
#include<semaphore>
#include<random>
#include<syncstream>
#include<latch>
using namespace std;
struct Runner
{string name;int time{ 0 };void run(latch& start, latch& end){//等待发令枪响start.wait();auto start_time = chrono::system_clock::now();mt19937 eng{ random_device{}() };uniform_int_distribution<unsigned int>uniform_int_distribution{ 0,2000 };this_thread::sleep_for(chrono::microseconds(9600000 + uniform_int_distribution(eng)));auto end_time = chrono::system_clock::now();time = chrono::duration_cast<chrono::milliseconds>(end_time - start_time).count();//跑完了end.count_down(1);//计数器减1}bool operator<(const Runner& other)const { return time < other.time; }
};int main()
{vector<Runner> runners = { Runner{"张三"},Runner{"李四"},Runner{"王五"},Runner{"赵六"},Runner{"钱七"}};const int runner_counter = runners.size();latch start(1);latch finish(runner_counter);vector<thread>threads;for (int i = 0; i < runner_counter; i++){threads.emplace_back(&Runner::run,&runners[i],ref(start),ref(finish));}cout << "发令枪响起" << endl;start.count_down();//阻塞等待计数器减为0//等待所有选手跑完finish.wait();//阻塞等待计数器减为0cout << "比赛结果:\n=============================\n";sort(runners.begin(), runners.end());for (auto& runner : runners){cout << runner.name << ":" << float(runner.time) / 1000 << "秒" << endl;}for (auto& t : threads){t.join();}return 0;
}

打印结果

 下面来看下barrier,与latch不同时，当barrier计数器为0时，开始新的一轮计时。

barrier是一个类模版，模版参数是一个可调用对象，每次计数器为0时会调用该函数。构造函数传递一个初始计数值。arrive将计数器减去传入的n.wait等待本阶段计数器到达为0. arrive_and_wait是arrive和wait一起使用，arrive_and_drop除了将本阶段计数减去n，还将下一阶段 初始计数值减去n. 

下面模拟一个幸存者游戏，每轮淘汰不符合条件的玩家，一共进行五轮游戏。

#include<array>
#include<vector>
#include<thread>
#include<iostream>
#include<mutex>
#include<algorithm>
#include<sstream>
#include<iomanip>
#include<semaphore>
#include<syncstream>
#include<numeric>
#include<future>
#include<random>
#include<barrier>
using namespace std;
class Participant
{
public:string name;Participant(string name) :name(name) {}template<typename BarrierType>void run(BarrierType& finish){mt19937 eng(random_device{}());uniform_int_distribution<unsigned int>uniform_dist(1000, 2000);for (int i = 0; i < 5; i++){auto rnd = uniform_dist(eng);this_thread::sleep_for(chrono::milliseconds(rnd));alive = rnd % 3;if (alive){finish.arrive_and_wait();//阻塞等待计数器 减到0}else{finish.arrive_and_drop();//当前减1并将下一轮减1break;}}}bool is_alive()const{return alive;}
private:bool alive = true;
};
int main()
{vector<Participant>participant = { Participant{"张三"},Participant{"李四"},Participant{"王五"},Participant{"赵六"},Participant{"钱七"}};const int participant_count = participant.size();int round = 0;auto on_complete = [&participant, &round]() noexcept {round++;cout << "第" << round << "轮幸存者：" << endl;int count = 0;for (auto& p : participant){if (p.is_alive()){cout << p.name << " ";count++;}}cout << endl;if (count == 0)cout << "无" << endl;};barrier finish(participant_count,on_complete);//计数器减为0时回调on_complete函数vector<thread>threads;for (auto& p : participant){threads.emplace_back([&p, &finish]() {p.run(finish);});}for (auto& thread : threads)thread.join();return 0;
}