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#点灯环节

点亮第一个灯

原理:从VCC正极电极过来，若碰到的组件是 1，那么就会不亮(因为两个都是高电平),若碰到的组件是 0,则会通过高低电平来促使灯发亮

#include <REGX52.H>void main()
{P2 = 0xFE;//由高往低数(从P27 ~ P20)1111 1110
}

让灯交互闪烁

#include <REGX52.H>
#include <INTRINS.H>
void Delay500ms()		//@12.000MHz
{unsigned char i, j, k;_nop_();i = 4;j = 205;k = 187;do{do{while (--k);} while (--j);} while (--i);
}void main()
{while(1){P2 = 0xFE;Delay500ms();P2 = 0xFF;Delay500ms();}
}
/*P2 = 0x49;Delay500ms();P2 = 0xB6;Delay500ms();
*/

流水灯实现

#include <REGX52.H>
void Delay1ms(unsigned int xms)		//@12.000MHz
{unsigned char i, j;while(xms){i = 2;j = 239;do{while (--j);} while (--i);xms--;}
}void main()
{while(1){P2 = 0xFE;Delay1ms(100);P2 = 0xFD;Delay1ms(100);P2 = 0xFB;Delay1ms(100);P2 = 0xF7;Delay1ms(100);P2 = 0xEF;Delay1ms(100);P2 = 0xDF;Delay1ms(100);P2 = 0xBF;Delay1ms(100);P2 = 0x7F;Delay1ms(100);}
}

独立按键控制灯

#include <REGX52.H>
void main()
{//P3_1 == 0表示按下if(P3_1 == 0)//注意这里的独立按键串口，第一个独立按键是P3_1的串口，第二个独立按键是P3_0的串口{P2_0 = 1;//表示寄存器中8位中的一位}else P2_0 = 0;
}

独立按键控制灯状态

注意:单片机上电后所有串口默认是高电平(1)

#include <REGX52.H>
void Delay1ms(unsigned int xms)		//@12.000MHz
{unsigned char i, j;while(xms){i = 12;j = 169;do{while (--j);} while (--i);xms--;}
}void main()
{while(1){//P2_0 = 0;if(!P3_1){Delay1ms(20);while(!P3_1);Delay1ms(20);P2_0 = ~P2_0;}}
}

实现二进制点灯方式

用需要定义一个字符去表示对应的二进制数，不断累加

#include <REGX52.H>void Delay1ms(unsigned int xms)		//@12.000MHz
{unsigned char i, j;while(xms){i = 2;j = 239;do{while (--j);} while (--i);xms--;}
}void main()
{unsigned char erjinzhi = 0;while(1){if(P3_1 == 0){Delay1ms(20);while(P3_1 == 0);Delay1ms(20);erjinzhi++;P2 = ~erjinzhi;}}
}

实现按键操控灯移向

单键操控

#include <REGX52.H>
void Delay1ms(unsigned int xms)		//@12.000MHz
{unsigned char i, j;while(xms){i = 2;j = 239;do{	while (--j);} 	while (--i);xms--;}
}void main()
{unsigned char Num = 0;P2 = ~(0x01);//需要初始化P2的第一位，因为不初始化会直接跳过第一位while(1){if(P3_1 == 0){Delay1ms(20);while(P3_1 == 0);Delay1ms(20);Num++;if(Num == 8)Num = 0;P2 = ~(0x01<<Num);}}
}

双键操控

#include <REGX52.H>
void Delay1ms(unsigned int xms)		//@12.000MHz
{unsigned char i, j;while(xms){i = 2;j = 239;do{	while (--j);} 	while (--i);xms--;}
}void main()
{unsigned char Num = 0;P2 = ~(0x01);//ÐèÒª³õʼ»¯P2´®¿ÚµÄÖµ£¬ÒòΪÈç¹û²»³õʼ»¯»áÌø¹ýµÚһλwhile(1){if(P3_1 == 0){Delay1ms(20);while(P3_1 == 0);Delay1ms(20);Num++;if(Num == 8)Num = 0;P2 = ~(0x01<<Num);}if(P3_0 == 0){Delay1ms(20);while(P3_0 == 0);Delay1ms(20);if(Num == 0)Num = 7;else Num --;P2 = ~(0x01 << Num);//这里为什么继续用左移//因为你的Num在执行K1按键的时候，Num自增了1，然后你在决定按K2的时候，Num又自减了1，相当于在K1的基础上右移了一位}}
}