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网站建设关键字优化舆情监测系统

wzjs 2025/8/24 3:21:34

网站建设关键字优化,舆情监测系统,新软件推广平台,wordpress填写表单下载这里写自定义目录标题有2个表，1个表user_class存在2个字段：class,codes，另一个表user_info有2个字段：code，name。期望返回每个class的codes及names,codes按照正序排序，names和codes顺序保持一致&#xff…

这里写自定义目录标题

有2个表，1个表user_class存在2个字段：class,codes，另一个表user_info有2个字段：code，name。
期望返回每个class的codes及names,codes按照正序排序，names和codes顺序保持一致？

with user_class as (select 'A' as class,'2\|1\|3' as codesunion all select 'B' as class,'2\|1' as codes
),
user_info as (select '1' as code,'TOM' as nameunion allselect '2' as code,'Jim' as nameunion allselect '3' as code,'An' as name
)
select w.class,regexp_replace(w.code,'[0-9]+_','') code,regexp_replace(w.name,'[0-9]+_','') name from (
select r.class,concat_ws(',',sort_array(collect_list(r.code))) code,concat_ws(',',sort_array(collect_list(r.name))) name
from (
select s.class,concat(lpad(s.rnt,4,'0'),'_',s.code) code,concat(lpad(s.rnt,4,'0'),'_',s.name) name
from (
select t1.class,t1.code,t2.name,row_number() over(partition by t1.class order by t1.code) rnt from (
selectt.class,s.code
from user_class t 
lateral view posexplode(split(codes,'\\|')) s as pos,code
) t1
left join
(select code,name
from user_info) t2
on t1.code = t2.code
) s
) r group by r.class
) w