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这道题我们固定a[1]和b数组的所有数组合，依次插入到堆里面，然后选n次最小的数，每次选出最小的数的时候，把a[i+1]和b数组的该数组合插入堆里面，直到输出n个数，我们程序就结束

#include <iostream>
#include <queue>
using namespace std;
const int N = 1e5+10;
typedef long long ll;
ll a[N],b[N];
struct node{ll sum;ll i;ll j;bool operator< (const node& x)const{return sum >x.sum;}
};
priority_queue <node> heap;
int main()
{ll n;cin >> n;for(int i = 1;i<=n;i++){cin >> a[i];}for(int i = 1;i<=n;i++){cin >> b[i];heap.push({(a[1]+b[i]),1,i});}for(int c = 1;c<=n;c++){node t = heap.top(); heap.pop();ll i = t.i; ll sum = t.sum; ll j = t.j;cout << sum << " ";heap.push({(a[i+1]+b[j]),i+1,j});}return 0;
}