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DOM4J解析XML, 修改xml的值

news 来源：原创 2025/5/25 13:17:39

1. 引入pom依赖

<dependency>
    <groupId>org.dom4j</groupId>
    <artifactId>dom4j</artifactId>
    <version>2.1.3</version>
</dependency>

2. 解析xml, 修改xml节点的值

import org.apache.commons.io.IOUtils;
import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;

import java.io.InputStream;
import java.nio.charset.StandardCharsets;
import java.util.List;

public class Dom4jParseUserXmlTest { 
	
	
    //业务数据xml格式
	public static String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" +
            "<DATA>\n" +
            "    <HEAD>\n" +
            "        <BIZID>AD03-1713863079</BIZID>\n" +
            "        <COUNT>1</COUNT>\n" +
            "        <CONSUMER>app</CONSUMER>\n" +
            "    </HEAD>\n" +
            "    <BODY>\n" +
            "        <ITEM>\n" +
            "            <CUST_NAME>张三</CUST_NAME>\n" +
            "            <CUST_SEX>0</CUST_SEX>\n" +
            "            <CUST_MOBILE>17812345678</CUST_MOBILE>\n" +
            "        </ITEM>\n" +
            "    </BODY>\n" +
            "</DATA>";
   
    public static void main(String[] args) { 
    	
        //创建解析器对象
        SAXReader saxReader=new SAXReader();
        try { 
            InputStream inputStream = IOUtils.toInputStream(
            		new String(xml), StandardCharsets.UTF_8.name()); 
            Document document = saxReader.read(inputStream);
            Element rootElement = document.getRootElement();
            System.out.println("1.------->root:"+rootElement.getName());

            System.out.println("2.------->获取root子标签列表");
            List<Element> usersSubElementList = rootElement.elements();
            for (Element userElement : usersSubElementList) { 
   
                System.out.println("DATA标签的子标签的名字是"+ userElement.getName());
                System.out.println("3.------->获取"+ userElement.getName() +"的子标签列表");
                List<Element> userSubElementList = userElement.elements();
                
                for (Element userSubElement : userSubElementList) { 
                	 if("BIZID".equals(userSubElement.getName())) {
                         //修改节点值
                		 userSubElement.setText("111111111111111111111111111");
                	 }
                     System.out.println("标签下的子标签名为:"+userSubElement.getName());
                     System.out.println("标签下的子标签文本是:"+userSubElement.getText());
                }
            }
//            //获取users标签的第一个标签
//              Element firstUserElement = rootElement.element("user");
//            //第一个user标签的子标签password的文本内容
//              String password = firstUserElement.attributeValue("password");
//              System.out.println(password);
        } catch (DocumentException e) { 
            e.printStackTrace();
        }
    }
}

3. 换个思路, XML转json, 然后解析json

3.1 用 Jackson 库

Jackson 是一个强大的 JSON 处理库，它也支持 XML 到 JSON 的转换。

添加 Jackson 依赖（Maven）：

<dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
    <version>2.15.0</version>
</dependency>
<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.15.0</version>
</dependency>

实现代码：

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;

public class XmlToJsonConverter {

    public static String convertXmlToJson(String xml) throws Exception {
        // 创建 XmlMapper 实例
        XmlMapper xmlMapper = new XmlMapper();
        // 将 XML 字符串解析为 JsonNode
        JsonNode node = xmlMapper.readTree(xml.getBytes());
        // 创建 ObjectMapper 实例
        ObjectMapper jsonMapper = new ObjectMapper();
        // 将 JsonNode 转换为 JSON 字符串
        return jsonMapper.writerWithDefaultPrettyPrinter().writeValueAsString(node);
    }

    public static void main(String[] args) {
        String xml = "<person><name>John Doe</name><age>30</age></person>";
        try {
            String json = convertXmlToJson(xml);
            System.out.println("JSON Output:\n" + json);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

输出：

{
  "person" : {
    "name" : "John Doe",
    "age" : "30"
  }
}

3.2 使用 org.json 库

<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>20231013</version>
</dependency>

代码

        // 示例XML字符串

        String xmlString= "<person><name>John Doe</name><age>30</age></person>";

        // 将XML转换为JSON
        JSONObject jsonObject = XML.toJSONObject(xmlString);
        String jsonString = jsonObject.toString(4); // 4是缩进空格数，用于美化输出
        System.out.println(jsonString);